C Program to check whether number is Armstrong number or not

 C Program to check whether number is Armstrong number or not

#include<stdio.h>

#include<math.h>

main()

{

  int num,i,j,temp,sum=0;;

  printf("Enter a number to know whether it is armstrong or not\n");

  scanf("%d",&num);

  temp=num;

  while(num>0)

  {

    i=num%10;

    sum+=i*i*i;

    num=num/10;

  }

  if(sum==temp)

  {

    printf("Giveb number %d is an armstrong number\n",temp);

  }

  else

  {

    printf("Giveb number %d is not an armstrong number since

         the sum of cubes of individual digits is %d\n",temp,sum);

  }

}

Output:

Enter a number to know whether it is armstrong or not

371

Giveb number 371 is an armstrong number